All categories

2 years ago

Can you add 4r + 4rg? Explain why or why not.

Mathematics

2 answers:

stira [4]2 years ago

8 0

Answer:

no, because 4r does not have the g variable.

Step-by-step explanation:

valentinak56 [21]2 years ago

3 0

No, you cant add things with multiple variables:)

You might be interested in

Equation with angles can someone please answer helpppp

Elden [556K]

Answer:

$x = 18°\\\angle A = 73°$

Step-by-step explanation:

By interior angle property on one side of the transversal.

$\angle A+ \angle B = 180°\\6x - 35° + 3x + 53° = 180°\\9x + 18° = 180°\\9x = 180° - 18°\\9x = 162°\\x = \frac{162°}{9}\\ \huge \red {\boxed {x = 18°}} \\\therefore \angle A = 6x - 35°\\\therefore \angle A = 6\times 18°- 35°\\\therefore \angle A = 108°- 35°\\ \huge \purple {\boxed{\therefore \angle A = 73°}} \\$

3 0

2 years ago

Reina and Sam are multiplying (8^4)^5 (7^3)^9<br><br> Is either of them correct?

PilotLPTM [1.2K]

Answer:

Sam is correct.

Step-by-step explanation:

Exponent rules state that when an number with an exponent is raised to a power, the two exponents multiply. For example, a^2^2=a^4.

6 0

2 years ago

Help pleaseee will mark brainliest

STatiana [176]

Ais the answer I’m pretty sure

4 0

2 years ago

Urgent!!!!!!!!!!!!!!!!!!

MAVERICK [17]

24 right box VEDR - 6(4)
9 Left triangle VMR - 0.5 (6)(3)
24 + 9 = 33

6 0

1 year ago

PLEASE HELP! I'll give 5 out of 5 stars, give thanks, and give as many points as I can.

Liula [17]

Answer:

$\boxed{\boxed{x=\dfrac{\pi}{3}\ \vee\ x=\pi\ \vee\ x=\dfrac{5\pi}{3}}}$

Step-by-step explanation:

$\cos(3x)=-1\iff3x=\pi+2k\pi\qquad k\in\mathbb{Z}\\\\\text{divide both sides by 3}\\\\x=\dfrac{\pi}{3}+\dfrac{2k\pi}{3}\\\\x\in[0,\ 2\pi)$

$\text{for}\ k=0\to x=\dfrac{\pi}{3}+\dfrac{2(0)\pi}{3}=\dfrac{\pi}{3}+0=\boxed{\dfrac{\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=1\to x=\dfrac{\pi}{3}+\dfrac{2(1)\pi}{3}=\dfrac{\pi}{3}+\dfrac{2\pi}{3}=\dfrac{3\pi}{3}=\boxed{\pi}\in[0,\ 2\pi)\\\\\text{for}\ k=2\to x=\dfrac{\pi}{3}+\dfrac{2(2)\pi}{3}=\dfrac{\pi}{3}+\dfrac{4\pi}{3}=\boxed{\dfrac{5\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=3\to x=\dfrac{\pi}{3}+\dfrac{2(3)\pi}{3}=\dfrac{\pi}{3}+\dfrac{6\pi}{3}=\dfrac{7\pi}{3}\notin[0,\ 2\po)$

7 0

2 years ago

Read 2 more answers