Answer:
The length of the other leg of this right angled triangle is 30 inches.
Step-by-step explanation:
We are given the following in the question:
A right angles triangle with the hypotenuse of 34 inches and the length of one of its legs is 16 inches.
Pythagoras theorem:
- The sum of of square of two sides of a triangle is equal to the square of the hypotenuse.
Let x inches be the length of the other leg of this right triangle.
Thus, we can write the equation:
Thus, the length of the other leg of this right angled triangle is 30 inches.
Answer:
Show blocks as addends and the sum as a bigger block
Step-by-step explanation:
<span> (17.) f(x)=x+3; g(x)=1/x^2
</span><span>If you take B f(x)=x+3 g(x)=1/x^2 plug the f(x) into the g(x) formula (in other words, f(x) becomes the x for g) g(x)=1/x^2 g(x)=1/(x+3)^2
</span>
The original functions are: f(n) = 500 and g(n) = [9/10]^(n-1)
A geometric sequence combining them is: An = f(n)*g(n) = 500*[9/10]^(n-1):
Some terms are:
A1= 500
A2 = 500*[9/10]
A3 = 500*[9/10]^2
A4 = 500*[9/10]^3
....
A11 = 500*[9/10]^10 ≈ 174.339
Answer: the third option, An = 500[9/10]^(n-1); A11 = 174.339
