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2 years ago

7

Suppose the students who scored 85 and 90 on the math test take the test again score 95

1 answer:

hodyreva [135]2 years ago

7 0

That means they went up by 10 points or 5 points

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Pls work out and give detail. Use the slope formula to determine the slope of each line.

kolbaska11 [484]

Answer:

$m=0$

Step-by-step explanation:

Given

See attachment

Required

Determine the slope of the line

From the attachment, we have the following points

$(x_1,y_1) = (-4,1)$

and

$(x_2,y_2) = (3,1)$

The slope m is then calculated using:

$m = \frac{y_2- y_1}{x_2 - x_1}$

Substitute values for the x's and y's

$m = \frac{1-1}{3 - (-4)}$

$m = \frac{1-1}{3 +4}$

$m = \frac{0}{7}$

$m=0$

<em>Hence, the slope is 0</em>

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2 years ago

Freee pointsss iggg :)

OlgaM077 [116]

Yayyy thanks a lottt can i also get brainliest

8 0

2 years ago

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Need answer for this please.

balu736 [363]

Answer:

y= - 5x+40

Step-by-step explanation:

I graphed this out. Remember that in parallel lines, the slopes are always the same.

4 0

2 years ago

List at least two advantages each of using a credit card and using cash.

Sonbull [250]

Credit Cards: You don't have to worry about how much cash you have at hand. You can get money when you need it.

Money: You won't overspend. You won't have to worry about fees.

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2 years ago

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Find an equation of the sphere with center (2, −10, 3) and radius 5. $$25=(x−2)2+(y−(−10))2+(z−3)2 use an equation to describe i

lana66690 [7]

In the $x,y$ plane, we have $z=0$ everywhere. So in the equation of the sphere, we have

$25=(x-2)^2+(y+10)^2+(-3)^2\implies(x-2)^2+(y+10)^2=16=4^2$

which is a circle centered at (2, -10, 0) of radius 4.

In the $x,z$ plane, we have $y=0$ , which gives

$25=(x-2)^2+10^2+(z-3)^2\implies(x-2)^2+(z-3)^2=-75$

But any squared real quantity is positive, so there is no intersection between the sphere and this plane.

In the $y,z$ plane, $x=0$ , so

$25=(-2)^2+(y+10)^2+(z-3)^2\implies(y+10)^2+(z-3)^2=21=(\sqrt{21})^2$

which is a circle centered at (0, -10, 3) of radius $\sqrt{21}$ .

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2 years ago