<em>Given - a+b+c = 0</em>
<em>To prove that- </em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
<em>Now we know that</em>
<em>when x+y+z = 0,</em>
<em>then x³+y³+z³ = 3xyz</em>
<em>that means</em>
<em> (x³+y³+z³)/xyz = 3 ---- eq 1)</em>
<em>Lets solve for LHS</em>
<em>LHS = a²/bc + b²/ac + c²/ab</em>
<em>we can write it as LHS = a³/abc + b³/abc + c</em><em>³</em><em>/abc</em>
<em>by multiplying missing denominators,</em>
<em>now take common abc from denominator and you'll get,</em>
<em>LHS = (a³+b³+c³)/abc --- eq (2)</em>
<em>Comparing one and two we can say that</em>
<em>(a³+b³+c³)/abc = 3</em>
<em>Hence proved,</em>
<em>a²/bc + b²/ac + c²/ab = 3</em>
The correct answer is 4> -3
Answer:
C=30
Step-by-step explanation:
Supposing that we have the lines
x+2=10y
and
3x+6=Yc.
Note that dividing by 3 the second line can be rewritten as
x + 2= Y c/3.
Remember that a line is written as 
, in our case, both lines have 
and 
. Therefore, in orther that the two lines are equal, we need that 
, hence 
Answer:
14x + 8
Explanation:
⇒ 4(5x+5) - 3(2x + 4)
distribute inside parenthesis
⇒ 4(5x) + 4(5) - 3(2x) - 3(4)
multiply the variables
⇒ 20x + 20 - 6x - 12
collect like terms
⇒ 20x - 6x + 20 - 12
subtract like term
⇒ 14x + 8
2.2to 4 pages in a minute because 12 divided by 3 is 4 and 12 divided by 5 is 2.2
