Answer:
decelerating hope this helps❤️
Answer:
Explanation:
Any gas at standard temperature and pressure (STP) has a volume of 22.4 liters per mole or 22.4 L/mol. We can create a proportion with this value.
Multiply both sides of the equation by 6.8 moles of krypton.
The units of moles of krypton will cancel.
The denominator of 1 can be ignored, so this becomes a simple multiplication problem.
If we round to the nearest whole number, the 3 in the tenths place tells us to leave the 2 in the ones place.
6.8 moles of krypton gas at standard temperature and pressure is equal to <u>152 liters</u>.
Answer:
(a) ΔSº = 216.10 J/K
(b) ΔSº = - 56.4 J/K
(c) ΔSº = 273.8 J/K
Explanation:
We know the standard entropy change for a given reaction is given by the sum of the entropies of the products minus the entropies of reactants.
First we need to find in an appropiate reference table the standard molar entropies entropies, and then do the calculations.
(a) C2H5OH(l) + 3 O2(g) ⇒ 2 CO2(g) + 3 H2O(g)
Sº 159.9 205.2 213.8 188.8
(J/Kmol)
ΔSº = [ 2(213.8) + 3(188.8) ] - [ 159.9 + 3(205.) ] J/K
ΔSº = 216.10 J/K
(b) CS2(l) + 3 O2(g) ⇒ CO2(g) + 2 SO2(g)
Sº 151.0 205.2 213.8 248.2
(J/Kmol)
ΔSº = [ 213.8 + 2(248.2) ] - [ 151.0 + 3(205.2) ] J/K = - 56.4 J/K
(c) 2 C6H6(l) + 15 O2(g) 12 CO2(g) + 6 H2O(g)
Sº 173.3 205.2 213.8 188.8
(J/Kmol)
ΔSº = [ 12(213.8) + 6(188.8) ] - [ 2(173.3) + 15( 205.2) ] = 273.8 J/K
Whenever possible we should always verify if our answer makes sense. Note that the signs for the entropy change agree with the change in mol gas. For example in reaction (b) we are going from 4 total mol gas reactants to 3, so the entropy change will be negative.
Note we need to multiply the entropies of each substance by its coefficient in the balanced chemical equation.
Answer: 5moles
Explanation:
1mole of a substance contains 6.02x10^23 molecules.
Then, 1mole of CO also contains 6.02x10^23 molecules.
If 1 mole of CO2 contains 6.02x10^23 molecules, it means Xmol of CO contains 3.01 E24 ie 3.01x10^24 molecules
Xmol of CO = 3.01x10^24 / 6.02x10^23
Xmol = 5moles