Answer:
38 cm from q1(right)
Explanation:
Given, q1 = 3q2 , r = 60cm = 0.6 m
Let that point be situated at a distance of 'x' m from q1.
Electric field must be same from both sides to be in equilibrium(where EF is 0).
=> k q1/x² = k q2/(0.6 - x)²
=> q1(0.6 - x)² = q2(x)²
=> 3q2(0.6 - x)² = q2(x)²
=> 3(0.6 - x)² = x²
=> √3(0.6 - x) = ± x
=> 0.6√3 = x(1 + √3)
=> 1.03/2.73 = x
≈ 0.38 m = 38 cm = x
Answer:
Flow rate of air is given as 83.33 cubic feet per minute
Explanation:
As we know that total volume of the air flow is given as
also we know that total time is
now we have flow rate given as
Answer:
The average speed of the bus, v = 1.55 m/s
Explanation:
Given that,
Number of blocks traveled by bus towards east = 6
Number of blocks traveled by bus towards north = 8
Length of each block = 100 m
Distance traveled by bus towards east 6 x 100 = 600 m
Distance traveled by bus towards north 8 x 100 = 800 m
The total distance traveled, d = 600 + 800 = 1400
Time taken by the bus to travel is, t = 15 minutes
The velocity is given by the formula
v = d/t m
Substituting the values in the above equation
v = 1400 m /(15 x 60) s
= 1.55 m/s
Hence, the average speed of the bus, v = 1.55 m/s
