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2 years ago

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A school track is shown. 1000 m 74 m The straightaway on each side measures 1,000 meters. The curves are semicircles with diamet

er 74 meters. What is the distance, in meters, around the entire track? Use the a button on your calculator and express your answer to the nearest hundredth. The distance is meters.

1 answer:

Lesechka [4]2 years ago

4 0

Answer:

You have Rs 2,400 in your account and the interest rate is 5%. After how many years

would you earn Rs 240 as interest.

Step-by-step explanation:

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The probability of choosing a 6 at random from a standard deck of playing cards is 1/13 what is the complement of the event of c

tekilochka [14]

To find the complement of an event you have to figure out what the probability is of not choosing a 6
since 1/13 is the probability that 6 is going to be choosen.
the other 12/13 is used for every other card accept for the 6:)
hope this is right
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5 0

2 years ago

A carpenter has a board that is 8 feet long. He cuts off two pieces. One piece is 3 1/2 feet long and the other is 2 1/3 feet lo

Aneli [31]

Add 3 1/2 and 2 1/3,

Firstly, find the common denominator. It is is 6

3 3/6 + 2 2/6

this gets you 5 5/6.

Take this away from 8:

8 - 5 5/6 = 2 1/6

So 2 1/6 of the board is left over.

6 0

2 years ago

A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40

malfutka [58]

PART A

The given equation is

$h(t) = - 16 {t}^{2} + 40t + 4$

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4$

We add and subtract

$- 16(- \frac{5}{4} )^{2}$

to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

This implies that,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4$

The quadratic trinomial above is a perfect square.

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4$

This finally simplifies to,

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29$

The vertex of this function is

$V( \frac{5}{4} ,29)$

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

$29$

PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

$- 16 ( t- \frac{5}{4}) ^{2} = - 29$

This implies that,

$( t- \frac{5}{4}) ^{2} = \frac{29}{16}$

$t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }$

$t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}$

$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

8 0

2 years ago

If the volume of a cube is 729 cm3, what is the surface area of the cube?

Vlada [557]

D hope i can helppppppp

6 0

3 years ago

Read 2 more answers

I desperately need this question answered. See attached image thanks so much

Dahasolnce [82]

For this case we must follow the steps below:

step 1:

We place each of the given points on a coordinate axis

Step 2:

We join the AC points (represented by the orange line)

We join the BD points (represented by the blue line)

It is observed that the resulting figure after placing the 4 points on a coordinate axis, turns out to be a rhombus.

In addition, the blue and orange lines turn out to be perpendicular, that is, they have an angle of 90 degrees between them. This can be verified by finding the slopes of each of the two straight lines (blue and orange), which must be opposite reciprocal, that is, they comply: $m1 * m2 = -1$

In this case, the slope of the orange line is $m1 = 1$ and that of the blue line is $m2 = -1$

Then $m1 * m2 = 1 * -1 = -1$ , it is verified that they are perpendicular.

Thus, the conclusion is that ABCD is a rhombus and AC is perpendicular to BD.

Answer:

See attached image

Option D

6 0

2 years ago