Answer:
step 1
Find the average growth per year of the populations of rabbits farm A
Over the first 2 years
for t=0
numbers of rabbits=5 (is not exact)
for t=2
numbers of rabbits=40
average=[40-5]/2---------> 17.5
step 2
Find the average growth per year of the populations of rabbits farm B
Over the first 2 years
for t=0
numbers of rabbits=5 (is not exact)
for t=2
numbers of rabbits=30
average=[30-5]/2---------> 12.5
step 3
Compare the average growth per year of the populations of rabbits on both farms
farm A=17.5
farm B=12.5
the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 5 rabbits per year.
therefore
the answer is the option C)
the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 6 rabbits per year.
Step-by-step explanation:
Answer:
bd=cc=oc2
Step-by-step explanation:
Answer:
it reduce the number by 6 mark me brainlist
Hello! So, the train travels 80 miles in an hour. 90 minutes is equivalent ot 1 ½ hours. In case you don't know, ½ of 80 is 40. To find the distance gone in 90 minutes, we can just add 80 and 40. 80 + 40 is 120. Another way to solve it is to multiply 80 by 1.5 and you would still get the same answer. There. The train will have gone 120 miles in 90 minutes.
You forgot the image , here if you want some free points to repost it just go to a point put a bogus answer in one of my questions . That mistake happens to me all the time
