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2 years ago

: Find absolute minimum and maximum values of (, ) = 2

Mathematics

1 answer:

ASHA 777 [7]2 years ago

7 0

F(x , y) = x + y - xy, D is the closed triangular region with vertices (0, 0), (0 , 2) , and (4 , 0)

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Add and express your answer in scientific notation (5.7 x 10^8) +(3.2 x 10^6)

kaheart [24]

5.7+3.2=8.9

10^8+10^6=10^14

(8.9+10^14)

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hope it helps

3 0

2 years ago

On her math test, Heidi correctly answered 35 of the 40 questions. What percentage of the questions did Heidi correctly answer?

Elena-2011 [213]

Answer:

Divide 35/40 = 87.5%

Step-by-step explanation:

3 0

2 years ago

Chicken cuties are on sale for 3.48 per pound How much will it cost to but 3.5 pounds

kramer

3.48 for 1 pound

You can put it in comparison,

3.48 / 1 = x / 3.5

And then cross-multiply it,
1x = 3.48 x 3.5
x = 12.18

5 0

2 years ago

A scientist inoculates mice, one at a time, with a disease germ until he finds 3 that have contracted the disease. If the prob

UkoKoshka [18]

Answer:

The probability that 8 mice are required is 0.2428.

Step-by-step explanation:

Given : A scientist inoculates mice, one at a time, with a disease germ until he finds 3 that have contracted the disease. If the probability of contracting the disease is two sevenths.

To find : What is the probability that 8 mice are required? The probability that that 8 mice are required is nothing ?

Solution :

Applying binomial distribution,

$P(X=r)=^nC_r p^rq^{n-r}$

Where, p is the probability of success $p=\frac{2}{7}$

q is the probability of failure q=1-p, $q=1-\frac{2}{7}=\frac{5}{7}$

n is total number of trials n=8

r=3

Substitute the values,

$P(X=3)=^8C_3 (\frac{2}{7})^3 (\frac{5}{7})^{8-3}$

$P(X=3)=\frac{8!}{3!5!}\times \frac{8}{343}\times (\frac{5}{7})^{5}$

$P(X=3)=\frac{8\times 7\times 6}{3\times 2\times 1}\times \frac{8}{343}\times \frac{3125}{16807}$

$P(X=3)=0.2428$

Therefore, the probability that 8 mice are required is 0.2428.

5 0

2 years ago

HELP ASAP!!!!

4vir4ik [10]

1. 64
2.32
3. 16
4. 8
5. 4
6. 2

6 0

2 years ago

Read 2 more answers