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2 years ago

14

Hurry please I need help on this

1 answer:

lubasha [3.4K]2 years ago

5 0

5/6-2/5 would be my guess

beacuse i would think the answer would be 1/3 but that is not on the multiple choice.

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Can someone PLEASE help me with this

Mekhanik [1.2K]

Answer:

4.5 u

Step-by-step explanation:

There are many ways to do it, the most easier is this:

Area=(b*h)/2

Area of ABD = (3*3)/2 = 4.5 u

3 0

2 years ago

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Find x. Leave answers in simplified radical form. (Step by step)

just olya [345]

Answer:

$\sf x = 4\sqrt{2}$

Given:

adjacent: 4 cm
hypotenuse: x cm
angle: 45°

<u>using cosine rule:</u>

$\sf cos(x) = \dfrac{adjacent}{hypotenuse}$

$\sf cos(45) = \dfrac{4}{x}$

$\sf x = \dfrac{4}{cos(45)}$

$\sf x = 4\sqrt{2}$

4 0

2 years ago

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Can y’all please help me answer these questions

mario62 [17]

Step-by-step explanation:

4.

⇒ $V = \pi r^{2}h$

⇒ $V = \pi(10)^{2}(40)$

⇒ $V = 4000\pi$

⇒ $V = 12566.4cm^{3}$

5.

⇒ $V = \frac{1}{3}\pi r^{2}h$

⇒ $V = \frac{1}{3}\pi (8)^{2}(h)$

As we know the radius and slant height, we can use Pythagoras' Theorem to find the perpendicular height.

⇒ $a^{2} + b^{2} = c^{2}$

⇒ $(8)^{2} + h^{2} = 20^{2}$

⇒ $h = \sqrt{20^{2} - 8^{2}}$

⇒ $h = 4\sqrt{21}$

Now substitute this into the volume formula.

⇒ $V = \frac{1}{3}\pi (8)^{2}(4\sqrt{21})$

⇒ $V = \frac{256\sqrt{21} }{3}\pi$

⇒ $V = 1228.5mm^{3}$

6.

⇒ $V = l^{3}$

⇒ $V = (3.1)^{3}$

⇒ $V = 29.8inches^{3}$

7.

⇒ $V = \frac{1}{3}lwh$

⇒ $V = \frac{1}{3}(12)(4)(6)$

⇒ $V = 96inches^{3}$

6 0

2 years ago

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Prove that ABCD is a rectangle.<br> A = (-4, 4)<br> B = (0,5)<br> C = (1, 1)<br> D = (-3,0)

kaheart [24]

Answer:

Draw it on a graph sheet

5 0

2 years ago

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I need help d:<br> Thank you plz

sladkih [1.3K]

For question<span> </span> 111. the value of x is x = 2/5

Sorry I couldn't answer other questions.. :(

But I hope this helped!!… :D
Please correct me if I'm wrong!!… :3

4 0

2 years ago

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