Answer:
4 would be the answer hopefully
For each bus there will be 9 students
Answer:
482
Step-by-step explanation:
We can see that the numbers shown resemble an arithmetic sequence because they have a common difference. The formula for the nth term of an arithmetic sequence is:
Where is the first term, is the nth term, and is the common difference. To find the 61st term, all we need is the first term and the common difference. By looking at what given, we can say the first term is 2. Now, to find the common difference, we find the difference of a term from the term before it. In this case we can do , which is , or the common difference. Since we have everything we need, it can be plugged into the equation:
So, the 61st term is 482.
1/7 + x = 2/3x
1/7 = 2/3x-x
1/7 = 2/3x - 1x
1/7 = -1/3x
-3/7 = x
688,747,536 ways in which the people can take the seats.
<h3>
</h3><h3>
How many ways are there for everyone to do this so that at the end of the move, each seat is taken by exactly one person?</h3>
There is a 2 by 10 rectangular greed of seats with people. so there are 2 rows of 10 seats.
When the whistle blows, each person needs to change to an orthogonally adjacent seat.
(This means that the person can go to the seat in front, or the seats in the sides).
This means that, unless for the 4 ends that will have only two options, all the other people (the remaining 16) have 3 options to choose where to sit.
Now, if we take the options that each seat has, and we take the product, we will get:
P = (2)^4*(3)^16 = 688,747,536 ways in which the people can take the seats.
If you want to learn more about combinations:
brainly.com/question/11732255
#SPJ!