Answer:
9
Step-by-step explanation:
We're using the Pythagorean theorem here since it's a right triangle.
a^2 (side) + b^2 (side) = c^2 (hypotenuse)
12 = a
x = b
15 = c
12^2 + b^2 = 15^2
144 + b^2 = 225
- 144 - 144 (subtracting 144 from both sides to isolate b)
b^2 = 81
(getting rid of the exponent by squaring both sides)
b = 9
x = 9
Answer: The proof is mentioned below.
Step-by-step explanation:
Here, Δ ABC is isosceles triangle.
Therefore, AB = BC
Prove: Δ ABO ≅ Δ ACO
In Δ ABO and Δ ACO,
∠ BAO ≅ ∠ CAO ( AO bisects ∠ BAC )
∠ AOB ≅ ∠ AOC ( AO is perpendicular to BC )
BO ≅ OC ( O is the mid point of BC)
Thus, By ASA postulate of congruence,
Δ ABO ≅ Δ ACO
Therefore, By CPCTC,
∠B ≅ ∠ C
Where ∠ B and ∠ C are the base angles of Δ ABC.
Answer:
-3/2
Step-by-step explanation:
We have to see where the point lies, check the x-axis from the graph.
(-3/2, 1/2)
x = -3/2
