9514 1404 393
Answer:
5/9 m/min
Step-by-step explanation:
The depth of the water is 2/5 of the depth of the trough, so the width of the surface will be 2/5 of the width of the trough:
2/5 × 2 m = 4/5 m
Then the surface area of the water is ...
A = LW = (18 m)(4/5 m) = 14.4 m²
The rate of change of height multiplied by the area gives the rate of change of volume:
8 m³/min = (14.4 m²)(h')
h' = (8 m³/min)/(14.4 m²) = 5/9 m/min
Answer:
true
Step-by-step explanation:
plug in u. u=e
25>= 5x5
25>=25
true
Answer:
72 ft
Step-by-step explanation:
Here, we want to get the maximum height the ball will reach
the maximum height the ball will reach is equal to the y-coordinate of the vertex of the equation
So we need firstly, the vertex of the given quadratic equation
The vertex can be obtained by the use of plot of the graph
By doing this, we have it that the vertex is at the point (3,72)
Thus, we can conclude that the maximum height the ball can reach is 72 ft
1 kilometer = 1000 meters so 12 kilometers = 12000 meters
10 laps (400 meters/lap) = 4000 meters
12000/4000 = 3
Answer: 3 days
2/11 ≈ 0.18 3/12 = 0.25.
So the answer is no, 2/11 isn't bigger than 3/12.
I hope this helps!