Answer:
There are no real solutions to this equation.
Hope This Helps!
It's scalene because all three sides are different
Y = tan (√ t )
We will use chain rule.
( tan x ) ` = sec² x
( √ t ) ` = 1 / 2√t
y ` = sec² (√ t ) · 1 / 2√t
y` = 1/cos² ( √ t ) · 1 / 2√t
Factorize the left hand side and equate the factors to zero.
Then, use the notation that : sec x = 1/cosx and csc x = 1/sinx
Result: x = ± π3 + 2πk , k∈Z