All categories

2 years ago

28 and 12 The GCF is

1 answer:

8 0

Answer: Greatest common factor (GCF) of 12 and 28 is 4. We will now calculate the prime factors of 12 and 28 then find the greatest common factor (greatest common divisor (gcd)) of the numbers by matching the biggest common factor of 12 and 28.

Step-by-step explanation: BRAINLESS PLEASE

You might be interested in

Complete the equation of the line whose slope is -2−2 and yy-intercept is (0,3)(0,3)

jeka57 [31]

The slope-intercept form:

y = mx + b

m - slope

b - y-intercept

We have the slope m = -2 and y-intercept (0, 3) → b = 3. Substitute:

7 0

2 years ago

How do you simplify 36 over 10

Studentka2010 [4]

Answer:

18/5

Step-by-step explanation:

36/10

First find a number that goes into both the two numbers.

...2 can go into both of them...

36 / 10

(÷2) (÷2)

18 / 5

Now we have to see if any other number goes in to these new numbers...

There are no numbers that goes into both...

Hope this helped! <3

8 0

2 years ago

Find the measurements of each angle

Lana71 [14]

GED is 43
CEB and AED is 90
GEB and FEA is 47

hope this helps!

4 0

2 years ago

Read 2 more answers

Find the root(s) of f (x) = (x + 5)3(x - 9)2(x + 1). -5 with multiplicity 3 5 with multiplicity 3 -9

faust18 [17]

Answer:

-5, multiplicity 3; +9, multiplicity 2; -1

Step-by-step explanation:

The roots of f(x) are those values of x that make the factors be zero. For a factor of x-a, the root is x=a, because a-a=0. If the factor appears n times, then the root has multiplicity n.

f(x) = (x+5)^3(x-9)^2(x+1) has roots ...

-5 with multiplicity 3
+9 with multiplicity 2
-1

4 0

2 years ago

Find the domain of the function y = 3 tan(23x)

solmaris [256]

Answer:

$\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

In other words, the $x$ in $f(x) = 3\, \tan(23\, x)$ could be any real number as long as $x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)$ for all integer $k$ (including negative integers.)

Step-by-step explanation:

The tangent function $y = \tan(x)$ has a real value for real inputs $x$ as long as the input $x \ne \displaystyle k\, \pi + \frac{\pi}{2}$ for all integer $k$ .

Hence, the domain of the original tangent function is $\mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

On the other hand, in the function $f(x) = 3\, \tan(23\, x)$ , the input to the tangent function is replaced with $(23\, x)$ .

The transformed tangent function $\tan(23\, x)$ would have a real value as long as its input $(23\, x)$ ensures that $23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2}$ for all integer $k$ .

In other words, $\tan(23\, x)$ would have a real value as long as $x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right)$ .

Accordingly, the domain of $f(x) = 3\, \tan(23\, x)$ would be $\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

4 0

1 year ago