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2 years ago

A student writes the equation for a line that has a slope of -6 and passes through the point (2, –8).

Mathematics

1 answer:

tester [92]2 years ago

3 0

Answer:

y -(-8) = -6(x - 2) or y - (-8) = -6x + 12

Step-by-step explanation:

gradient(m) = -6 point (2,-8)

equation of a line is given as;

y - y1 = m(x - x1)

y - (-8) = -6(x - 2)

y - (-8) = -6x - 12

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2 years ago

Write an equation of the line that passes through the given points. (-1,5) and (2, - 7)

Vanyuwa [196]

Answer:

The equation of the straight line is 4x +y = 1

Step-by-step explanation:

Step(i):-

Given points are (-1,5) and ( 2,-7)

Slope of the line

$m =\frac{y_{2}-y_{1} }{x_{2} -x_{1} } =\frac{-7-5}{2-(-1)} = \frac{-12}{3} = -4$

slope of the line m = -4

Step(ii):-

The equation of the straight line passing through the point (-1,5) and having slope 'm' = -4

$y - y_{1} = m( x-x_{1} )$

y - 5 = -4 ( x-(-1))

y -5 = -4 x -4

4 x + y -5 +4=0

4x +y -1 =0

Final answer:-

The equation of the straight line is 4x +y = 1

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2 years ago

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Mkey [24]

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Step-by-step explanation:

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Answer:

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7 73 37 104

8 69 35 0

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