Answer:
the integer in question lies between 13 and 14.
Step-by-step explanation:
Review the perfect squares in the neighborhood of 194. The first that came to my mind was 225 (the squre of 15), and then 196 (the square of 14), and then 169, the square of 13.
Since 169 < x^2 < 196, the integer in question lies between 13 and 14.
Check with a calculator: √194 ≈ 13.93
How to find rapidly the coordinates of Q:
since Q is the center of gravity of the triangle ABC, so we have the following vector relationship
vecQA +vecQB +vecQC =<span>vec0
</span><span>vecQA=(x-3, y+2)
</span><span>vecQB=(x-1, y+5)
</span><span>vecQC=(x-7, y+5)
</span><span>vec0=(0, 0)
</span>
so, vecQA +vecQB +vecQC =<span>vec0 is equivalent to
</span>x-3 +x-1+x-7 =0, and y+2+y+5+<span>y+5=0 so 3x-11=0 implies x=11/3
</span><span>and 3y+12=0 implies y=-12/3
finally the </span><span>the coordinates of point Q is (11/3, -4)</span><span>
</span>
Answer:
Step-by-step explanation:
-2x²-3x+8=0
disc.=b²-4ac=(-3)²-4(-2)(8)=9+64=73>0
it has two real irrational solutions.
2.5... if you question was 5/2
Answer:
B.
Step-by-step explanation: