2 because 8 divided by 4 is 2.
Answer:
<u>a</u>
Step-by-step explanation:
Given :
⇒ P (Sumit) = 1/2
⇒ P (Sujan) = 1/3
⇒ P (Rakesh) = 1/a
⇒ P (total) = 3/4
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Solving :
⇒ 1/2 × 1/3 × 1/a = 3/4
⇒ 1/6 × 1/a = 3/4
⇒ 2/12 × 1/a = 9/12
⇒ a = <u>9/2</u>
Let's build the equation counting how many x's and 1's are there on each side.
On the left hand side we have 5x's and 8 1's, for a total of 
On the left hand side we have 3x's and 10 1's, for a total of 
So, the equation we want to solve is
Subtract 3x from both sides:
Subtract 8 from both sides:
Divide both sides by 2:
The cost function is
c = 0.000015x² - 0.03x + 35
where x = number of tires.
To find the value of x that minimizes cost, the derivative of c with respect to x should be zero. Therefore
0.000015*2x - 0.03 = 0
0.00003x = 0.03
x = 1000
Note:
The second derivative of c with respect to x is positive (= 0.00003), so the value for x will yield the minimum value.
The minimum cost is
Cmin = 0.000015*1000² - 0.03*1000 + 35
= 20
Answer:
Number of tires = 1000
Minimum cost = 20
(1/2)(3/6)=1/4
The probability of rolling a head (or tail for that matter is 1/2)
The probability of rolling less than 4 with a die is 3/6)
Thus the probability of both occurring is 1/4
