Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 = -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12 = -16t^2 + 128t
Divide each side by -16
-12/-16 = -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one
Answer:
Isn't that just soild liquid and gas atoms?
The image is showing how the atoms change depending on which state of matter it is, so if it is a soild the atoms would be really compacted as it moves slower, if it's a liquid then it's more looser than a soild, but more compacted than a gas, and a gas is just moving a lot and has a lot more space.
^^ That would be the answer if you on the states of matter or something like that unit.
Answer:
Step-by-step explanation:
Adding both equations will make it:
Putting x = 10 will make it:
= 3(1000)-40+1
= 3000-39
= 2961