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2 years ago

12

The two loudspeakers in the drawing are producing identical sound waves. The waves spread out and overlap at the point P. What i

s the difference in the two path lengths if point P is at the third sound intensity minimum from the central sound intensity maximum

1 answer:

Damm [24]2 years ago

5 0

Answer:

5/2π

Explanation:

According to quizlet the answer is 5/2π

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A car moves with a speed 72km/h, the driver uses the brakes, the car stops after 8 seconds, calculate its speed after 10 seconds

vampirchik [111]

The acceleration of the car is solved by subtracting the initial speed from the final speed then dividing the result by the elapsed time.

initial speed = 72 km/hr = 20 m/s

final speed = 0 m/s

elapsed time = 5 seconds

acceleration = (0 m/s – 20 m/s) / 5 s

acceleration = - 20m/s / 5 s

acceleration = -4 m/s^2

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2 years ago

Which energy is cuased by an objects vibration

amm1812

D. sound energy........

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Each rarefraction on a longitudinal wave correspond to what point on a transverse wave?

morpeh [17]

Answer: In a longitudinal wave, the crest and trough of a transverse wave correspond respectively to the compression, and the rarefaction. A compression is when the particles in the medium through which the wave is traveling are closer together than in its natural state, that is, when their density is greatest.

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2 years ago

Mr. Roberts drives his car away from his house at a constant speed. Which of the following represents

zepelin [54]

Speed is represented by distance divided by time. Graphically, constant speed is represented by a horizontal line on a speed-time graph.

<u>Explanation</u>

In a very literal sense speed is considered to be scalar quantity and denotes how fast or quick objects move. Therefore, speed is considered to be the velocity or swiftness of an object to cover a certain amount of distance.
There three types of speed high speed, average speed, and zero speed. Any object which moves at very high speed or moves very fast and quickly and subsequently can cover the considerable distance is called high-speed object. On the other hand, the average speed of an object is defined as the total distance covered divided by the time taken to cover that distance. Again when the object doesn't cover any distance at a given time or any object which has got no movement in it is called zero speed object.
Constant speed objects are those objects which move at a constant speed. Constant speed here refers to mean objects which move at the same speed without increasing or decreasing.If we try to represent constant speed on the diagram or through graph it can be done by drawing a horizontal line on the speed-time- graph. Here Mr. Robert drives his car at a constant speed means that he was driving his car without increasing or decreasing the speed or at the same speed.It has the same increase in distance in the given time. Time increases at the right and distance increase constantly with time.

4 0

2 years ago

A motorcyclist started a race from START line and from rest, and accelerated with the acceleration of 2 m/s2 for 12 seconds. The

ElenaW [278]

Answer:

The total distance is 280 [m]

Explanation:

In order to solve this problem we must use the expressions of kinematics. The clue to solve this problem is that the motorcyclist starts from rest, i.e. its initial speed is zero.

$v_{f} =v_{o} +(a*t)$

where:

Vf = final velocity [m/s]

Vo = initial velocity = 0

a = acceleration = 2 [m/s²]

t = time = 12 [s]

Vf = 0 + (2*12)

Vf = 24 [m/s]

With this velocity, we can calculate the displacement using the following expression.

$v_{f} ^{2} =v_{o} ^{2} +2*a*x$

where

x = distance traveled [m]

24² = 0 + (2*2*x)

x = 576/(4)

x = 144 [m]

Note: The positive sign in the equations is because the car is accelerating, it means its velocity is increasing.

The other important clue to solve this problem in the second part is that the final velocity is now the initial velocity.

We must calculate the final velocity.

$v_{f}= v_{i} +(a*t)$

Vf = final velocity [m/s]

Vi = initial velocity = 24 [m/s]

a = desacceleration = 5 [m/s²]

t = time = 4 [s]

Vf = 24 + (4*5)

Vf = 44 [m/s]

With this velocity, we can calculate the displacement using the following expression.

$v_{f} ^{2} =v_{o} ^{2} +2*a*x$

where

x = distance traveled [m]

44² = 24² + (2*5*x)

x = 1360/(10)

x = 136 [m]

Note: The positive sign in the equations is because the car is accelerating, it means its velocity is increasing.

Therefore the total distance is Xt = 144 + 136 = 280 [m]

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2 years ago