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2 years ago

8

Plz help me with this problem! (I would put this for 25-50 points but then ppl don't give real answers they just say random thin

gs.) What is N? Use the seesaw principle.

2 answers:

Tom [10]2 years ago

8 0

Answer:

N sould = 10

Step-by-step explanation:

Naya [18.7K]2 years ago

7 0

Answer:

5 feet

Step-by-step explanation:

38xN=10(4)+15(10)

38N=40+150

38N=190

N=5

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I need help with 14 and 15!?

Levart [38]

Answer:

15

Step-by-step explanation:

Pythagorean theorem states that the hypogenous of a right triangle is $c=\sqrt{a^{2}+b^{2}}$ . The hypogenous is the longest part of the triangle which is directly across from the 90 degree angle.

a = 9

b = 12

so,

$c = \sqrt{9^{2}+12^{2} } = 15$

7 0

2 years ago

Solve the system of equations:x + 3y - z = -4 2x - y + 2z = 13 3x - 2y - z = -9

tatiyna

Answer:

The solution to the system of equations is

$\begin{gathered} x=\frac{179}{13} \\ \\ y=-\frac{279}{39} \\ \\ z=-\frac{48}{13} \end{gathered}$

Explanation:

Giving the system of equations:

$\begin{gathered} x+3y-z=-4\ldots\ldots\ldots\ldots\ldots\ldots..........\ldots\ldots\ldots\ldots.\ldots\text{.}\mathrm{}(1) \\ 2x-y+2z=13\ldots\ldots...\ldots\ldots\ldots\ldots..\ldots..\ldots\ldots\ldots\ldots\ldots.(2) \\ 3x-2y-z=-9\ldots\ldots\ldots.\ldots\ldots\ldots\ldots....\ldots\ldots.\ldots\ldots\ldots\text{.}\mathrm{}(3) \end{gathered}$

To solve this, we need to first of all eliminate one variable from any two of the equations.

Subtracting (2) from twice of (1), we have:

$5y-4z=-21\ldots\ldots\ldots\ldots\ldots.\ldots.\ldots..\ldots..\ldots\ldots.\ldots..\ldots\text{...}\mathrm{}(4)$

Subtracting (3) from 3 times (1), we have

$3y-5z=-3\ldots\ldots...\ldots\ldots..\ldots\ldots\ldots\ldots\ldots.\ldots\ldots\ldots\ldots\ldots..\ldots\ldots(5)$

From (4) and (5), we can solve for y and z.

Subtract 5 times (5) from 3 times (4)

$\begin{gathered} 13z=-48 \\ \\ z=-\frac{48}{13} \end{gathered}$

Using the value of z obtained in (5), we have

$\begin{gathered} 3y-5(-\frac{48}{13})=-3 \\ \\ 3y+\frac{240}{13}=-3 \\ \\ 3y=-3-\frac{240}{13} \\ \\ 3y=-\frac{279}{13} \\ \\ y=-\frac{279}{39} \end{gathered}$

Using the values obtained for y and z in (1), we have

$\begin{gathered} x+3(-\frac{279}{39})-(-\frac{48}{13})=-4 \\ \\ x-\frac{279}{13}+\frac{48}{13}=-4 \\ \\ x-\frac{231}{13}=-4 \\ \\ x=-4+\frac{231}{13} \\ \\ x=\frac{179}{13} \end{gathered}$

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8 months ago

Write a first step question and answer.Then solve the problem.The store owner gets a shipment of 7 boxes of games.There are 6 ga

n200080 [17]

(7 x 6) - 18 = 24 games left

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3 years ago

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Given that f(x) = x2 + 3x + 6 and g(x) = the quantity of x plus two, over three, solve for f(g(x)) when x = 1

MaRussiya [10]

Easy
f(g(1))
evaluate g(1) then plug thatin for x in f(x)
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f(g(1))=
f(1)=(1)^2+3(1)+6
f(1)=1+3+6
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docker41 [41]

Answer:

C

Step-by-step explanation:

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