All categories

2 years ago

PLEASE HELP!!!!! !!!!!!!!!!!!

Mathematics

1 answer:

valina [46]2 years ago

3 0

Answer:

31.9secs

6,183.3m

Step-by-step explanation:

Given the equation that models the height expressed as;

h(t ) = -4.9t²+313t+269

At the the max g=height, the velocity is zero

dh/dt = 0

dh/dt = -9,8t+313

0 = -9.8t + 313

9.8t = 313

t = 313/9.8

t = 31.94secs

Hence it takes the rocket 31.9secs to reach the max height

Get the max height

Recall that h(t ) = -4.9t²+313t+269

h(31.9) = -4.9(31.9)²+313(31.9)+269

h(31.9) = -4,070.44+9,984.7+269

h(31.9) = 6,183.3m

Hence the maximum height reached is 6,183.3m

You might be interested in

In the figure below, triangle JKL is isosceles, with JK = LK, and triangle LMN is equilateral. K M M N L Note: picture not drawn

Musya8 [376]

Answer: 56

Step-by-step explanation:

6 0

2 years ago

The hypotenuse of a right triangle is 9 inches long and another side is 6 inches. Find the length of the missing side. Round you

olga nikolaevna [1]

A² + b² = c²
a² = c² - b²
a² = 9² - 6²
a² = 81 - 36
a² = 45
a = √45
a ≈ 6.7082
a = 6.7

3 0

2 years ago

Help ppppppppppppllllllllllllllllsssssssss

marissa [1.9K]

Answer:

option b)

tan²θ + 1 = sec²θ

Step-by-step explanation:

The Pythagorean trigonometric identity is a trigonometric identity expressing the Pythagorean theorem in terms of trigonometric functions.

hypotenuse² = height² + base²

Given in the questions are some pythagorus identities which except of b) are all incorrect as explained below.

sin²θ + 1 = cos²θ incorrect

<h3>sin²θ + cos²θ = 1 correct</h3><h3 /><h3>2)</h3>

by dividing first identity by cos²θ

sin²θ/cos²θ + cos²θ/cos²θ = 1/cos²θ

<h3>tan²θ + 1 = sec²θ correct</h3><h3 /><h3>3)</h3>

1 - cot²θ = cosec²θ incorrect

by dividing first identity by sin²θ

sin²θ/sin²θ + cos²θ/sin²θ = 1/sin²θ

<h3>1 + cot²θ = cosec²θ correct</h3><h3 /><h3>4)</h3>

1 - cos²θ = tan²θ

not such pythagorus identity exists

4 0

2 years ago

Read 2 more answers

Part 2 out of 2

olganol [36]

Answer:

more than your rent

Step-by-step explanation:

hahahaha

4 0

2 years ago

A raffle offers one $8000.00 prize, one $4000.00 prize, and five $1600.00 prizes. There are 5000 tickets sold at $5 each. Find t

Harman [31]

Answer:

The expectation is $E(1 )= -\$ 1$

Step-by-step explanation:

From the question we are told that

The first offer is $x_1 = \$ 8000$

The second offer is $x_2 = \$ 4000$

The third offer is $\$ 1600$

The number of tickets is $n = 5000$

The price of each ticket is $p= \$ 5$

Generally expectation is mathematically represented as

$E(x)=\sum x * P(X = x )$

$P(X = x_1 ) = \frac{1}{5000}$ given that they just offer one

$P(X = x_1 ) = 0.0002$

Now

$P(X = x_2 ) = \frac{1}{5000}$ given that they just offer one

$P(X = x_2 ) = 0.0002$

Now

$P(X = x_3 ) = \frac{5}{5000}$ given that they offer five

$P(X = x_3 ) = 0.001$

Hence the expectation is evaluated as

$E(x)=8000 * 0.0002 + 4000 * 0.0002 + 1600 * 0.001$

$E(x)=\$ 4$

Now given that the price for a ticket is $\$ 5$

The actual expectation when price of ticket has been removed is

$E(1 )= 4- 5$

$E(1 )= -\$ 1$

4 0

2 years ago