Answer:
(2c³ -20c² -10c) -(c² -40c +100)
Step-by-step explanation:
<u>Profit</u>
For a problem involving cost, revenue, and profit, you are expected to know that <em>profit is the difference between revenue and cost</em>. That is, if it costs you $2 to make a necklace you sell for $10, your profit is $10 -2 = $8.
<u>Problem</u>
The problem gives you polynomial expressions for revenue and cost, and asks you to combine them to make an expression for profit. In this first part, we simply show <em>how</em> we will combine them. (We presume a later part of the question will ask you to simplify the result.)
profit = revenue - cost
Substituting the given expressions, we have ...
profit = (2c³ -20c² -10c) -(c² -40c +100) . . . . . matches last choice
Answer:
soln,
price of textbook = $40
tax% = 10%
now,
tax amount = 10% of $40
= 10\100*40
= 10*4/10
= 40/10
= $4.
again,
final price = cost of textbook+tax
=$40+$4
=$44.
Step-by-step explanation:
so the total price of a Textbook is $40 which is 100% and the tax is 10% so you need to find tax from the price of the textbook which is 10% of the price of the textbook then add the price of the textbook with the tax amount which is the final cost .
Answer:
Step-by-step explanation:
Recall that the notion of the derivative of a function is the rate of change of it. So it kind of tells us how much the value of functioin changes as the independt variable increases or decreases. If it is positive, this means that the function will increase as the indepent variable increases, and if it is negative, that means that the function will decrease as the indepent variable increases.
a) Since f(x) is the number of units you can make out of x units of raw material, it is natural to think that the more material you have, the more units you can make, so we expect f'(x) to be positive.
b) The company buys each unit of raw material at the price w. So the product wx represents the total cost of the raw material used to produce f(x) units. Since each produced unit is sell at the price of p, then the product pf(x) represents the total income for selling all f(x) units.Recall that the profit is the difference between the total income and the total cost of production. Hence, the profit in this case is represented by the formula pf(x)-wx.
c) Recall that a function h(x) that is differentiable attains it's maximum when it's derivative is 0 and it's second derivative is negative.
In this case, we know that the derivative of the profit function, evaluated at x* must be 0, since it is a maximum. So, using the rules of derivation, we know that the derivative of the profit function is pf'(x)-w. Hence,
pf'(x*)-w =0. From where we know that f'(x*)=w/p.
Answer:
d, 700
Step-by-step explanation:
it's the only one that makes sense
