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2 years ago

13

If two capacitors, A and B, have the same area and dielectric constant, but the distance between the plates of A is twice the di

stance between the plates of B, which has the higher capacitance? Explain your answer.

1 answer:

emmasim [6.3K]2 years ago

7 0

Answer:

Plate B will have a higher capacitance

Explanation:

One of the conditions affecting the capacitance of a capacitor is spacing between plates, the greater the spacing the lesser the capacitance and vice versa.

Hence plate B will have the B will have higher capacitance since the spacing is less when compared with that of plate A

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¿Por qué si cargas a uno de tus compañeros por cierto tiempo no estás realizando un trabajo mecánico?

VladimirAG [237]

Answer:

I will answer this in English, we can translate it to:

Why if you charge a mate by an amount of time you are not doing work?

This happens because work is defined as the displacement done by a force:

W = d*F

where W is work, d is the distance, and F is the force.

This means that the amount of time that you are charging your mate does not affect the mechanical work, the only time that you are doing work is when you are lifting him.

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2 years ago

A proton initially has v=4.0i^−2.0j^+3.0k^ and then 4.0 s later has v=−2.0i^−2.0j^+5.0k^ (in meters per second). For that 4.0 s,

pishuonlain [190]

Answer:

$a_{avg}=-1.5i+0.5k$

$1.58113883008\ m/s^2$

$-18.43^{\circ}\ or\ 161.57^{\circ}$

Explanation:

u = 4.0i−2.0j+3.0k v = −2.0i−2.0j+5.0k

Average acceleration is given by

$a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{-2-4, -2+2, 5-3}{4}\\\Rightarrow a=-1.5i-0j+0.5k$

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The magnitude is

$a_{avg}=\sqrt{(-1.5)^2+0.5^2}\\\Rightarrow a_{avg}=1.58113883008\ m/s^2$

The magnitude is $1.58113883008\ m/s^2$

The angle is

$\theta=tan^{-1}\dfrac{a_z}{a_x}\\\Rightarrow \theta=tan^{-1}\dfrac{0.5}{-1.5}\\\Rightarrow \theta=-18.43^{\circ}\ or\ 161.57^{\circ}$

The angle between $a_{avg}$ and the positive direction of the x axis is $-18.43^{\circ}\ or\ 161.57^{\circ}$

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2 years ago

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wariber [46]

Answer:

The minimum thickness of the film and the wavelength of the light in air are $1.197\times10^{-7}\ m$ and 371 nm.

Explanation:

Given that,

Refractive index of soap= 1.34

Refractive index of glass= 1.55

Wavelength = 642 nm

(I). We need to calculate the minimum thickness

Using formula of thickness

$t=\dfrac{(2m+1)\lambda}{4n}$

Where, m = 0 for constrictive

Put the value into the formula

$t=\dfrac{(642\times10^{-9})}{4\times1.34}$

$t=1.197\times10^{-7}\ m$

(II). We need to calculate the wavelength

Using formula of wavelength

$\lambda=\dfrac{2nt}{m}$

Where, m = 1

Put the value into the formula

$\lambda=\dfrac{2\times1.55\times1.197\times10^{-7}}{1}$

$\lambda=371\ nm$

Hence, The minimum thickness of the film and the wavelength of the light in air are $1.197\times10^{-7}\ m$ and 371 nm.

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2 years ago

A person's center of mass is very near the hips, at the top of the legs. Model a person as a particle of mass mm at the top of a

muminat

Answer:

$\mathbf{v_{max} = \sqrt{gL}}$

Explanation:

Considering an object that moving about in a circular path, the equation for such centripetal force can be computed as:

$\mathbf {F = \dfrac{mv^2}{2}}$

The model for the person can be seen in the diagram attached below.

So, along the horizontal axis, the net force that is exerted on the person is:

$mg cos \theta = \dfrac{mv^2}{L}$

Dividing both sides by "m"; we have :

$g cos \theta = \dfrac{v^2}{L}$

Making "v" the subject of the formula: we have:

$v^2 = g Lcos \theta$

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So, when $\theta$ = 0; the velocity is maximum

∴

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Hence; the maximum walking speed for the person is $\mathbf{v_{max} = \sqrt{gL}}$

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