Given the function f(x)= √x+7, find the value of x when f(x)=1

1 answer:

7 0

F(x) = 1, so we make the entire equation equal 1.

1 = sqrt(x) + 7

To make x by itself subtract 7 from both sides

-6 = sqrt(x)

Square both sides to remove sqrt from x.

36 = x

The value of x is 36

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A normal distribution has a mean of 137 and a standard deviation of 7. Find the z-score for a data value of 121. Incorrect Round

Neko [114]

Answer:

The z-score for a data value of 121 is -2.29.

Step-by-step explanation:

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 137, \sigma = 7$