Answer:
a=21
AB=23.9
BC=19.5
CD=(23.9)
AD=19.5
Step-by-step explanation:
Each pair of parallel sides are equal in a parallelogram. Sense both pairs use the same variable we can just choose the easiest to solve which would be:
a-1.5=19.5
add 1.5 to both sides
a=21
now substitute 21 in for a in each equation.
AB=CD so
AB=23.9
BC=AD so
BC=19.5
CD=(21)+2.9 so
CD=(23.9)
AD is given so
AD=19.5
Amar makes 8 dollars an hour for raking leaves
8
Answer:
It is not normally distributed as it has it main concentration in only one side.
Step-by-step explanation:
So, we are given that the class width is equal to 0.2. Thus we will have that the first class is 0.00 - 0.20, second class is 0.20 - 0.40 and so on(that is 0.2 difference).
So, let us begin the groupings into their different classes, shall we?
Data given:
0.31 0.31 0 0 0 0.19 0.19 0 0.150.15 0 0.01 0.01 0.19 0.19 0.53 0.53 0 0.
(1). 0.00 - 0.20: there are 15 values that falls into this category. That is 0 0 0 0.19 0.19 0 0.15 0.15 0 0.01 0.01 0.19 0.19 0 0.
(2). 0.20 - 0.40: there are 2 values that falls into this category. That is 0.31 0.31
(3). 0.4 - 0.6 : there are 2 values that falls into this category.
(4). 0.6 - 0.8: there 0 values that falls into this category. That is 0.53 0.53.
Class interval frequency.
0.00 - 0.20. 15.
0.20 - 0.40. 2.
0.4 - 0.6. 2.
Answer:
j = 0 or j = 30
Step-by-step explanation:
j² - 30j = 0
Factorise j out of both terms on the left side.
j (j-30) = 0
Apply zero product rule.
j = 0 or j-30 = 0
Find the value of j.
j = 0 or j = 30