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2 years ago

Explain why a city that receives 10 hours more light each day has colder average temperatures. Explain

Chemistry

1 answer:

Anestetic [448]2 years ago

3 0

Explanation:

This would be similar to how the poles work in the North and South. Due to their placement, they recieve much more sun light than the rest of the Earth since we rotate horizontally. However, their placement also makes them farther from the sun than the rest of Earth, therefore not receiving as much heat.

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2 years ago

What is the molarity of 5.74 liters of solution made with 246 grams of iron (III) chloride (FeCl3)? Answer with 3 SDs.

geniusboy [140]

Answer:

0.264 mol/L

Explanation:

Data obtained from the question includes:

Volume = 5.74L

Mass of FeCl3 = 246 g

Molarity =?

Next, we shall determine the number of mole in 246g of FeCl3.

This is illustrated below:

Mass of FeCl3 = 246g

Molar mass of FeCl3 = 56 + (35.5x3) = 162.5g/mol

Number of mole of FeCl3 =..?

Mole = Mass /Molar Mass

Number of mole of FeCl3 = 246/162.5

Number of mole of FeCl3 = 1.514 mol

Now, we can obtain the molarity of the solution as follow:

Molarity = mole /Volume

Volume = 5.74L

Mole of FeCl3 = 1.514 mol

Molarity = 1.514/5.74

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5 0

2 years ago

A compound is found to consist of 34.5% sodium, 16.4% boron, and 48.6% oxygen. What is the empirical formula?

NARA [144]

Answer: The empirical formula is $NaBO_2$

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given:

Mass of Na= 34.5 g

Mass of B= 16.4 g

Mass of O = 48.6 g

Step 1 : convert given masses into moles.

Moles of Na = $\frac{\text{ given mass of Na}}{\text{ molar mass of Na}}= \frac{34.5g}{23g/mole}=1.5moles$

Moles of B = $\frac{\text{ given mass of B}}{\text{ molar mass of B}}= \frac{16.4g}{11g/mole}=1.5moles$

Moles of O = $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{48.6g}{16g/mole}=3moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Na = $\frac{1.5}{1.5}=1$

For B = $\frac{1.5}{1.5}=1$

For O = $\frac{3}{1.5}=2$

The ratio of Na: B: O= 1: 1: 2

Hence the empirical formula is $NaBO_2$

7 0

2 years ago