Answer:
<h2>an+1 = 2×7ⁿ</h2>
Step-by-step explanation:
98÷14
=7
686÷98
=7
4 802÷686
=7
33 614÷4 802
=7
Then the common ratio q for this sequence is 7
recursive formula : an+1 = q×an = ?
an= a1 × qⁿ⁻¹
=2×7ⁿ⁻¹
an+1 = q×an
= 7×(2×7ⁿ⁻¹)
= 2×7ⁿ
The answer is the first option: 1) > the quantity times minus all over
The explanation is shown below:
1. To solve this problem you must pply the following proccedure:
2. Move the term to the left member. As the variable is negative, multiply the expression by and change the direction of the sign:
Answer: The equilibrium point is where; Quantity supplied = 100 and Quantity demanded = 100
Step-by-step explanation: The equilibrium point on a demand and supply graph is the point at which demand equals supply. Better put, it is the point where the demand curve intersects the supply curve.
The supply function is given as
S(q) = (q + 6)^2
The demand function is given as
D(q) = 1000/(q + 6)
The equilibrium point therefore would be derived as
(q + 6)^2 = 1000/(q + 6)
Cross multiply and you have
(q + 6)^2 x (q + 6) = 1000
(q + 6 )^3 = 1000
Add the cube root sign to both sides of the equation
q + 6 = 10
Subtract 6 from both sides of the equation
q = 4
Therefore when q = 4, supply would be
S(q) = (4 + 6)^2
S(q) = 10^2
S(q) = 100
Also when q = 4, demand would be
D(q) = 1000/(4 + 6)
D(q) = 1000/10
D(q) = 100
Hence at the point of equilibrium the quantity demanded and quantity supplied would be 100 units.
Answer:
Answer as follows...
Step-by-step explanation:
interior angles are 3,4,5,6
exterior angles are 1,2,7,8
vertical angles are 2and3, 1and4, 6and7, 5and8
corresponding angles are 2and6 1and5 3and7 4and8
alternate interior angles are 4and5 3and6
alternate exterior angles are 1and8 2and7
same side interior angles are 3and5 4and6