To solve this problem we will apply the principle of energy conservation. Here we have that the gravitational potential energy must be equal to the kinetic energy of the body. So,

$PE = KE$

$\frac{GMm}{R} = \frac{1}{2} mv^2$

Here,

m = mass of projectile

G = Gravitational Universal constant

M = Mass of the planet

R = Total height from center of mass of the planet

v = Velocity

Rearraning to find the velocity we have,

$\frac{GM}{R} = \frac{1}{2} v^2$

$v = \sqrt{2\frac{GM}{R}}$

Our values are given as,

$M = 2*10^{24} kg$

$r = 7*10^6 m$

$h = 6*10^6 m$

$R = h+r = 13*10^6m$

$G = 6.67259*10^{-11} N\cdot m^2/kg^2$

Replacing we have,

$v = \sqrt{2\frac{(6.67259*10^{-11})(2*10^{24})}{13*10^6}}$

$v = 4531.12m/s$

Therefore the initial speed of the projectile must be 4531.12m/s

4 0

2 years ago

When two objects collide, what happens to the total momentum of the interacting forces? Explain why (use the vocabulary: momentu

kherson [118]

<h2><u>Collision of objects:</u></h2>

In a closed system, when two or more particles collide, the sum of momentum of two particles before and after collision will always be the same. In elastic collision, kinetic energy and momentum of a particle remains conserved. Whereas in inelastic collision, momentum remains same before and after collision but some of the particle's kinetic energy may be converted to other forms of energy.

A moving particle or object may possess kinetic energy and it depends mainly on its motion and mass. The kinetic energy is converted into potential energy and converted back to kinetic energy during collision of small particles.

7 0

2 years ago

Calculate the work WAB done by the electrostatic force on a particle of charge q as it moves from A to B.

Semmy [17]

Answer:

$W_{AB} = EqL$