Answer:
Both flights approach each other at a speed of 624.70 Knots. The FAA minimum separation is not violated as both airplanes are 7.26 Nautical miles away from each other at the time when one of the flights( flight AA) passes through Frada Heights.
Step-by-step explanation:
To solve this kind of problem, the knowledge of concept of relative velocity is needed as the first question requested how fast the flights were approaching each other. To find the minimum distance between both flights, the closest point of approach between both flights should be taken into consideration which was Frada heights. Flight AA passes through Frada Heights in a shorter time of 0.079 hours. This is the time at which both flights approach each other the closest and so the minimum distance (separation) between them. This was calculated to be 7.26NM which is greater than the FAA's minimum this requirement for flight was not violated.
Detailed calculation steps can be found in the attachment below.
You have to divide both sides by 12 so 12f/12 =24/12 is f = 2
7/10 is 0.7
0.7 x 16 yields 11.2
11.2 is also 11 1/5
or 56/5
Answer: B or the second choice
Step-by-step explanation:
well for triangle DEF since E is on the top left, it should be on the bottom right. While F was on the bottom right, it would be on the top left where E originally was. The angles inside has the same situation with E and F, however D stills stays at the top because when reflected like a mirror, D stays at the top. Sorry it’s long and hope this helps!
PS u also took a pic of the correct answer lol XD
Answer:
The father is 40 and the son is 4.
Step-by-step explanation:
40 + 5 = 45.
4 +5=9.
45 divided by 5 = 9