The powder is made through a chemical reaction (saponification) between an alkaline base with oils is to be expected that there will always be a residual alkali. PH around <span>11.5
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You need to use the ideal gas law (PV=nRT) and solve for n. ((3.50atm•10.0L)/(0.0821(L•atm/mol•K)•304K) = n = 1.40 moles. 1 mole of Cl2 = 70.9 gm/mole. The mass would be 99.43 gm
Answer:
8.59 g
2.25 g
Explanation:
According to the given situation the calculation of grams of PbO and grams of NaCL is shown below:-
Moles of Pb(OH)CL is
= 0.0385 mol
Mass of PbO needed is
After solving the above equation we will get
= 8.59 g
Mass of NaCL needed is
After solving the above equation we will get
= 2.25 g
Therefore we have applied the above formula.
The correct name for the hydrocarbon would be option 2. 2 - methyl - 2 - pentene.