hello :<span>
<span>an equation of the circle Center at the
A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =0 and b = 0 (Center at the origin)
r = OP....p(-8,3)
r² = (OP)²
r² = (-8-0)² +(3-0)² = 64+9=73
an equation of the circle that satisfies the stated conditions.
Center at the origin, passing through P(-8, 3) is : x² +y² = 73</span></span>
Answer:
b^20
Step-by-step explanation:
when the exponents have one inside and the other outside, they are multiplied.
The line is starting from right side and goes thorough left .
Means
- Its starts from 1st Quadrant and goes to 3rd Quadrant.(+ve to -ve)
- Y is infinite
Hence
The solution is
![\\ \sf\longmapsto (0,\infty]](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%280%2C%5Cinfty%5D)
Answer:
length, width, and height are (b+2), (b-2), (b+3)
Step-by-step explanation:
Doing what the problem statement tells you to do, you get ...
(b^3 +3b^2) -(4b +12)
= b^2(b +3) -4(b +3) . . . . . factor each pair of terms
= (b^2 -4)(b +3) . . . . . . . . . write as a product
= (b -2)(b +2)(b +3) . . . . . . use the factoring of the difference of squares
The three factors are (b-2), (b+2), and (b+3). We have no clue as to how to associate those with length, width, and height. We just know these are the dimensions of the box.
Step-by-step explanation:
Part 1) <span>What is the maximum volume of a square pyramid that can fit inside a cube with a side length of 18 cm?
we know that
[volume of a square pyramid]=(1/3)*b</span>²*h
where
b is the length side of the square base-----> 18 cm (is equal to the length side of cube)
h is the height---------> 18 cm (is equal to the length side of cube)
[volume of a square pyramid]=(1/3)*18²*18----> 1944 cm³
the answer Part 1) is
c. 1,944 cm³
Part 2) <span>Find the volume of the cylinder in terms of Pie. The diagrams are not drawn to scale.
</span>
volume of a cylinder=pi*r²*h
for r=2.2 m
h=12 m
volume of a cylinder=pi*2.2²*12-----> volume=58.08*pi m³
the answer Part 2) is
58.08*pi m³
