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2 years ago

12

A phone company worker needs to know the height of a cell tower, so he decides to use a 2 m pole and shadows cast by the sun, as

shown in the diagram. Both shadows end at point B. What is the height of the tower?

1 answer:

olganol [36]2 years ago

6 0

I always found it easiest to draw out the picture

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Answer:

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Boys = 30

<h3>Percentage</h3>

$\sf \frac{30}{75} \times 100\% \\ \sf= \frac{10}{25} \times 100\% \\ \sf = \boxed{ \bold{ \red{40\%}}}$

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If sin(theta) =4/5 and is in quadrant 2, the value of cot(theta

iren [92.7K]

$\sin\theta= \frac{4}{5} 
\\
\\\sin^2\theta+\cos^2\theta=1
\\ \cos\theta=\pm \sqrt{1-\sin^2\theta} =\pm \sqrt{1-( \frac{4}{5})^2 } =\pm \sqrt{1- \frac{16}{25} } =\pm \sqrt{\frac{9}{25} }=\pm \frac{3}{5}}$

$\theta \in II \Rightarrow \cos\theta\ \textless \ 0 \Rightarrow \cos\theta=-\frac{3}{5}$

$\cot\theta= \frac{\cos\theta}{\sin\theta}= \frac{-\frac{3}{5}}{\frac{4}{5}} =- \frac{3}{4}$

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