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2 years ago

Simplify problem if possible

Mathematics

1 answer:

sergeinik [125]2 years ago

3 0

$\left(\frac{(x^4y^{-2})^4}{(2x^2)^2\cdot2x^0y^3}\right)^2=\\
\left(\frac{x^{16}y^{-8}}{4x^4\cdot2y^3}\right)^2=\\
\left(\frac{x^{16}y^{-8}}{8x^4y^3}\right)^2=\\
\left(\frac{x^{12}y^{-11}}{8}\right)^2=\\
\frac{x^{24}y^{-22}}{64}$

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Find the values of P for which the quadratic equation 4x²+px+3=0?

klasskru [66]

<h3><u>Correct Questions :- </u></h3>

Find the values of P for which the quadratic equation 4x²+px+3=0 , provided that roots are equal or discriminant is zero .

<h3><u>Solution</u>:- </h3>

Let us Consider a quadratic equation αx² + βx + c = 0, then nature of roots of quadratic equation depends upon Discriminant (D) of the quadratic equation.

For equal roots

D = 0

$\quad\green{ \underline { \boxed{ \sf{Discriminant, D = β² - 4αc}}}}$

So,

$\sf{ β² - 4αc = 0}$

Here,

α = 4
β = p
c = 3

Now,

$\begin{gathered}\implies\quad \sf p²- 4 \times 4 \times 3 =0 \end{gathered}$

$\begin{gathered}\implies\quad \sf p²- 48 =0 \end{gathered}$

$\begin{gathered}\implies\quad \sf p²=48\end{gathered}$

$\begin{gathered}\implies\quad \sf p=±\sqrt{48}\end{gathered}$

$\begin{gathered}\implies\quad \sf p=±\sqrt{2 \times 2 \times 2 \times 2 \times 3} \end{gathered}$

$\begin{gathered}\implies\quad \sf p=± 2\times 2\sqrt{ 3 }\end{gathered}$

$\begin{gathered}\implies\quad \boxed{\sf{p=±4\sqrt{ 3 }}}\end{gathered}$

Thus, the values of P for which the quadratic equation 4x²+px+3=0 are-

4√3 and -4√3.

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2 years ago

How do you write 9.59 x 102 in a standard form?

Nataly [62]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

I need answers ASAP! Thanks!

Daniel [21]

Step-by-step explanation:

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44. 7

53. Airplanes can be traveling on different planes, one plane above the other. Cars on the same intersection are on the same plane.

a. You can choose (4 * 3 * 2)/(3 * 2) = 4 groups of 3 points in which order does not matter.

One of those combinations does not have K, so 3 combinations of the 4 have K.

p = 3/4

b. p = 1 since any three points are always coplanar.

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2 years ago

Use the Four-Step Approach to solve the given problem.

V125BC [204]

Answer:30 mi

3s = 2.5(s+2)

3s = 2.5s + 5

3s - 2.5s = 5

.5s = 5

s = 5/.5

s = 10 mph to the beach

Confirm this by finding the actual distance each way, should be the same

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Step-by-step explanation:

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2 years ago

Given the coordinates A (5, 7, -2) and B (8, 3, 4) in 3d space, express AB as:

lys-0071 [83]

The vector AB is found by subtracting the coordinates of point B from the coordinates of point A => (8, 3, 4) - (5, 7, - 2)

(8, 3, 4) - (5, 7, - 2) = (3, - 4, 6)

=>

a) a 3 x 1 column =

| 3 |
| -4 |
| 6 |

b) xi + yj + zk

=> 3i - 4j + 6k

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3 years ago