Over a period of 30 days a student studied the night sky and recorded his observations. One night he watched a shooting star str
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Answer: (a) The solubility of CuCl in pure water is .
(b) The solubility of CuCl in 0.1 M NaCl is .
Explanation:
(a) Chemical equation for the given reaction in pure water is as follows.
Initial: 0 0
Change: +x +x
Equilibm: x x
And, equilibrium expression is as follows.
x =
Hence, the solubility of CuCl in pure water is .
(b) When NaCl is 0.1 M,
,
,
Net equation:
= 0.1044
So for,
Initial: 0.1 0
Change: -x +x
Equilibm: 0.1 - x x
Now, the equilibrium expression is as follows.
K' =
0.1044 =
x =
Therefore, the solubility of CuCl in 0.1 M NaCl is .