Recall your d = rt, distance = rate * time.
b = speed rate of the boat.
c = speed rate of the current.
keeping in mind that, as the boat goes Upstream, against the current, it's speed is not "b", but is really " b - c ", because the current is subtracting speed from it.
likewise, when the boat is going Downstream, because is going with the current, is really going faster at " b + c ".
what is the speed of the boat? well, 61 + c = b.
Answer:
120
Step-by-step explanation:
45 + 15 (6 -1)
45 + 15 (5)
45 + 75
120
Cos(<span>θ) < 0, so we know it would be in Quadrant 2 or 3
then csc(</span>θ) = 257, but csc(θ) =
= 257
==> sin(<span>θ) =
it is positive, so now we can determine that is in Quadrant 2
sin(</span>θ) = opp./hyp both of opp and hyp are positive but adj suppose to negative because that way it leads the cos(<span>θ) < 0
</span>cos(<span>θ) = adj/hyp
</span>Pythereom to find the adj:
cosθ =
tanθ =
cos<span>θ = </span>