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2 years ago

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Which situation illustrates quadratic equation?

1 answer:

Anna007 [38]2 years ago

4 0

<em>Complete Question:</em>

<em>Which situation illustrates quadratic equation? </em>

<em>a. The length of a rectangular board is 3m longer than its width and its perimeter is 25m. </em>

<em>b. Joey paid at least P2,000 for the shirt and pants.The cost of pants is P700 more than the shirt. </em>

<em>c. A garden's length is 7m longer than its width and the area is 18 square meter. </em>

<em>d. A lot costbP4,000 per square meter and the area is 120 square meters.</em>

Answer:

C.

Step-by-step explanation:

Required

Determine which option answers the question, correctly.

From the list of given options, only option c answers the question correctly.

This is shown below.

Represent

Length with l and Width with w, such that:

$l = 7 + w$

Area (A) is calculated as thus:

$A = l * w$

Substitute 7 + w for l and 18 for A.

This gives:

$18 = (7 + w) * w$

Open Bracket

$18 = 7w + w^2$

Reorder

$w^2 + 7w = 18$

Subtract 18 from both sides

$w^2 + 7w - 18= 18 - 18$

$w^2 + 7w - 18= 0$

See that the above expression is a quadratic equation.

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Let's solve your equation step-by-step.

$\frac{1}{4} x^2+5=0$

For this equation: $a=0.25, b=0, c=5$

$0.25x^2 + 0x + 5 = 0$

Step 1: Use quadratic formula with $a=0.25, b=0, c=5.$

$x = \frac{-b ± \sqrt{b^2 - 4ac} }{2a}$

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