Answer:
d = 4.9 m
Explanation:
It is mentioned that a stone is dropped from a certain height. It is required to find the distance covered by it in one second.
The initial speed of the stone is equal to 0 as it was at rest. Let d is the distance covered by the stone.
Using second equation of motion :
Put u = 0 and a = g
So, the distance covered by it in one second is 4.9 m.
The material that the snails are moving on affects their speed. On a smooth material, (petri dish) the snails moved the fastest. On a rough material (sandpaper) the snails moved the slowest. On dirt, a compromise between smooth and rough, the snails moved at a medium pace. The material and possibly friction affect this.
To solve this problem we will apply the linear motion kinematic equations. We will find the two components of velocity and finally by geometric and vector relations we will find both the angle and the magnitude of the vector. In the case of horizontal speed we have to
The vertical component of velocity is
Here,
h = Height
g = Gravitational acceleration
t = Time
= Vertical component of velocity
The direction of the velocity will be given by the tangent of the components, then
The magnitude is given vectorially as,
Therefore the angle is 55.59° and the velocity is 26.37m/s