23/7+61/3 is done first due to PEMDAS
so the lcm of 7 and 3 is 21
So 23*3 + 61*7 divide the whole by 21 which is 7*3
The answer will come out to 496/21
Then outside the bracket the whole is times 34/3
So 34/3*496/21=
16864/64
We can’t simplify it more so that’s the answer
Answer:
-6,4
Step-by-step explanation:
-6 times 4 is -24. -6 plus 4 is -2
It is important because if you are adding and subtracfing and the decimals are off when your done with the equation you might end up with two decimals or numbers in the wrong place
In order to find the area of a triangle you have to multiply the base with the height then divide by 2.
hope this helps
Answer:
Class interval 10-19 20-29 30-39 40-49 50-59
cumulative frequency 10 24 41 48 50
cumulative relative frequency 0.2 0.48 0.82 0.96 1
Step-by-step explanation:
1.
We are given the frequency of each class interval and we have to find the respective cumulative frequency and cumulative relative frequency.
Cumulative frequency
10
10+14=24
14+17=41
41+7=48
48+2=50
sum of frequencies is 50 so the relative frequency is f/50.
Relative frequency
10/50=0.2
14/50=0.28
17/50=0.34
7/50=0.14
2/50=0.04
Cumulative relative frequency
0.2
0.2+0.28=0.48
0.48+0.34=0.82
0.82+0.14=0.96
0.96+0.04=1
The cumulative relative frequency is calculated using relative frequency.
Relative frequency is calculated by dividing the respective frequency to the sum of frequency.
The cumulative frequency is calculated by adding the frequency of respective class to the sum of frequencies of previous classes.
The cumulative relative frequency is calculated by adding the relative frequency of respective class to the sum of relative frequencies of previous classes.
