20/110 because there's 20 kids in her third period but 110 overall hope I helped in time
cos4x = cos2x
We know that:
cos2x = 1-2cos^2 x
==> cos4x = 1-2cos^2 (2x)
Now substitute:
==> 1-2cos^2 (2x) = cos2x
==> 2cos^2 (2x) + cos2x - 1 = 0
Now factor:
==> (2cos2x -1)(cos2x + 1) = 0
==> 2cos2x -1 = 0 ==> cos2x =1/2 ==> 2x= pi/3
==> x1= pi/6 , 7pi/6
==> x1= pi/6 + 2npi
==> x2= 7pi/6 + 2npi
==> cos2x = -1 ==> 2x= pi ==> x3 = pi/2 + 2npi.
<span>==> x= { pi/6+2npi, 7pi/6+2npi, pi/2+2npi}</span>
Answer:
A. An Algebraic Expression
Step-by-step explanation:
Since we have no equal sign in the problem, we know that it is an expression. An equation has an equal sign and another value so we can simplify to find the value of whatever variable we are working with. We also know that it is not anything numerical because we are working with variables. With this information we will see that the correct answer is A.
Best of Luck!
Answer:
<u>C) 2parts that are one eight each.</u>
Step-by-step explanation:
The reason I chose <u>C)</u> as the correct answer is becasue I evaluated it with the steps below.
A) - 8 parts that are one fourth each.
<u>This cannot be correct because it would surpase the 2/8ths (would be over).</u>
B) - 4 parts that are one-half each.
<u>This cannot be correct because it would surpass the 2/8ths (would be over).</u>
C) - 2parts that are one eight each.
<u>This can be correct because 2 parts have 1/8th. 1/8 + 1/8 = 2/8.</u>
D) - 2parts that are one fourth each.
This cannot be correct because the denominator is not 8, it is 4 meaning it wouldn't fit into the format the question asked for (which was 2/8).
<u>This makes the correct answer C).</u>
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I hope this helps you understand and helps you in your question.