Answer:
13212
Step-by-step explanation:
Answer:
- question 2 answer is C. (-1,7) and (6,28)
- question 3 answer is A. it is possible for a system of equations composed of linear function and a quadratic function to have 3 solutions.
- question 4 answer is (1,6)
P.s. if any question is wrong then I'm sorry. :(
Step-by-step explanation:
question 4
y=2x^2-5x+9
y= 2x^2+5x-1
y= 2x^2-5x+9=2x^2+5x-1
x=1
y= 2×1^2+5×1-1
y=6
E=3x6x6
e=3x36
e=108
hope it helps
y-y1 = m (x-x1) y+3 = (1/4)(x+4) [using point (x1,y1)] or y–1 = (1/4)(x–12) [using point (x2,y2] [let's use this one since you did] To put this into Standard Form (Ax+By=C), y–1 = (1/4)(x–12) 4y - 4 = x - 12 -x + 4y - 4 = -12 [subtract x from both sides] -x + 4y = -8 [add 4 to both sides] x - 4y = 8 [multiply by (-1) to have x-coefficient positive
1. 1 1/3
2. 10 7/8
3. 4 7/15
4. 4/7
I hope this helps. :)
