The area of a trapezoid is
where B and b are the two bases, and h is the height. The two bases have to be parallel, and the height must be perpendicular to both bases.
Even though we are used to have horizontal bases and vertical height, it's not mandatory, since a simple rotation doesn't affect the dimensions or the area of the trapezoid.
So, in this case, the two vertical segments are actually the bases of the trapezoid, and the horizontal segment is the height. So, the formula for the area yields
Distribute the 3 to the parentheses. Q=3r+3/r
Next multiply both sides by r to get rid of the division sign.
Qr=3r+3
Subtract 3r on both sides and you get Qr-3r=3
Since both numbers have an r in it, we can factor out the r
r(Q-3)=3
Then we divide Q-3 on both sides
r=3 / (Q-3)
A=162sq......... bless up
Answer:
g =6/5 g=-5/2
Step-by-step explanation:
(5g − 6)(2g + 5) = 0
Using the zero product property
(5g − 6) =0 (2g + 5) = 0
5g-6+6 =0+6 2g+5-5=0-5
5g =6 2g =-5
5g/5 = 6/5 2g/2 =-5/2
g =6/5 g=-5/2
What exactly is your question?
