The joint F.D.P of a bivariate VA (X, Y) is given
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Answer: B. 11%
Step-by-step explanation:
Let A = Event that students eat breakfast in the morning.
B= Event that students floss their teeth.
We are given P(A)=57%=0.57
P(B)=80%=0.80
P(A∩B) = 46% =0.46
Now, the probability that a student from this class eats break feast but does not floss their teeth :-
Hence, the probability that a student from this class eats break feast but does not floss their teeth= 11%