If trapezoid JKLM is translated according to the rule (x, y) → (x + 8, y − 3), what are the coordinates of point L'?

2 answers:

5 0

<span>Another answer: According to the figure, the coordinates of JKLM are, J(-7,-2), K(-4,-2), L(-2,-5) and M(-9,-5) JKLM is translated to J'K'L'M' by means of the rule (x+8, y-3), we should know that (x, y) are coordinates of the pre image, to find the coordinates of each image we have (x', y') such that x' =x+8, and y' =y-3. Therefore, the coordinates of L' can be found by L'(-2+8, -5-3)=(6, -8) the final answer is L'(6, -8).</span>

Anvisha [2.4K]3 years ago

3 0

Answer: The answer is C (8,-6) not (6,-8).

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