In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The lower end of the interval is given by:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}}$

The upper end of the interval is given by:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}}$

The length of the interval is the subtraction of the upper end by the lower end, so it is:

$L = 2z\sqrt{\frac{\pi(1-\pi)}{n}}$

This means that the length is inverse proportional to the square root of the size of the sample.

So, if the sample size is multiplied by 4, the length of the interval is going to decrease by a factor of 2.

4 0

2 years ago

Please help I will give brainliest

Hunter-Best [27]

Answer:

Step-by-step explanation:

IM RLY SORRY IF THIS IS WRONG IM DOING THIS FORM MEMORY

so I'm pretty sure u the arch equals twice the angle

so pi/2*2 = pi so D

hope it helppsss

trying not to dieT-T

7 0

1 year ago

Someone text me on sc queenalyssa_05

tekilochka [14]

Okay! You’re a girl right? Lol

5 0

2 years ago