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2 years ago

9

When you produce a current/electron flow through a copper wire with a generator; the wire itself carrying the current (electron

flow) also produces
a magnetic field.

True or false ?

1 answer:

amm18122 years ago

5 0

True is the right answer

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Chromium(III) oxide reacts with hydrogen sulphide gas to form chromium(III) sulphide and water. How many grams of hydrogen sulph

ahrayia [7]

Answer:

165.726 g.

Explanation:

For the balanced equation:

<em>Cr₂O₃ + 3H₂S → Cr₂S₃ + 3H₂O,</em>

It is clear that 1 mol of Cr₂O₃ and 3 mol of H₂S to produce 1 mol of Cr₂S₃ and 3 mol of H₂O.

Firstly, we need to calculate the no. of moles of 324.8 g of chromium(III) sulphide:

no. of moles of Cr₂S₃ = mass/molar mass = (324.8 g)/(200.19 g/mol) = 1.62 mol.

Now, we can find the "no. of grams" of H₂S are needed:

<u><em>Using cross multiplication:</em></u>

3 mol of H₂S produces → 1 mol of Cr₂S₃, from stichiometry.

??? mol of H₂S produces → 1.62 mol of Cr₂S₃.

∴ The no. of moles of H₂S are needed = (3 mol)(1.62 mol)/(1 mol) = 4.86 mol.

∴ The "no. of grams" of H₂S are needed = (no. of moles of H₂S)(molar mass of H₂S) = (4.86 mol)(34.1 g/mol) = 165.726 g.

7 0

2 years ago

HALPPPPPP MEH YALL<br> THANKSSSSSS

Ronch [10]

Aye daddy

Lucky thing i just came back xD

Its 78.66 to the nearest sig fig

U can google it 2

Since it takes 4ever to type it out i wrote it intead srry if its messy lol

4 0

2 years ago

Read 2 more answers

a radioisotope has a half life of three hours how much of a 120g sample remains after 9 hours. what will the g amount be after 3

aksik [14]

$\huge\boxed{♔︎Answer♔︎}$

60g after 3 hours, 30g after 6 hours and 15g after 9 hours

Explanation:

Weight of the radioactive sample = 120g

half life time period = 3 hours

(a) The weight of sample after 3 hours

$\textsf{ No. of half lives} = \sf \cancel\frac{3}{3} = 1$

The fraction of sample left

$\sf { \frac{1}{2} }^{1} = \frac{1}{2}$

Mass of the sample left

$\sf \frac{1}{2} \times 120 = \cancel\frac{120}{2} = 60g$

<u>6</u><u>0</u><u>g</u><u> </u><u>of</u><u> </u><u>sample</u><u> </u><u>is</u><u> </u><u>left</u><u> </u><u>after</u><u> </u><u>3</u><u> </u><u>hours</u>

(b) The weight of sample after 6 hours

$\textsf{ No. of half lives} = \sf \cancel\frac{6}{3} = 2$

The fraction of the sample left

$\sf { \frac{1}{2} }^{2} = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4}$

Mass of the sample left

$\sf \frac{1}{4} \times 120 = \cancel\frac{120}{4} = 30g$

<u>3</u><u>0</u><u>g</u><u> </u><u>of</u><u> </u><u>sample</u><u> </u><u>is</u><u> </u><u>left</u><u> </u><u>after</u><u> </u><u>6</u><u> </u><u>hours</u>

(c) The weight of sample after 9 hours

$\textsf {No. of half lives} = \sf \cancel\frac{9}{3} = 3$

The fraction of sample left

$\sf { \frac{1}{2} }^{3} = \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{1}{8}$

Mass of sample left

$\sf \frac{1}{8} \times 120 = \cancel \frac{120}{8} = 15g$

<u>1</u><u>5</u><u>g</u><u> </u><u>of</u><u> </u><u>sample</u><u> </u><u>is</u><u> </u><u>left</u><u> </u><u>after</u><u> </u><u>9</u><u> </u><u>hours</u><u>.</u>

3 0

1 year ago

What type of orbital overlap is responsible for the π bond between carbon and oxygen in the molecule below?

Vinvika [58]

According to picture below, p atomic <span>orbitals overlap are responsible for the π bond between carbon and oxygen.
Both carbon and oxygen have sp2 hybridization in this carbonyl group. Carbon has three sigma bonds with sp2 orbitals and oxygen has one sigma bond with sp2 and two free electron pairs with sp2 orbitals. Pi bonds are formed between two p orbitals.</span>

7 0

3 years ago

How can people conserve water at home?

dlinn [17]

Answer:

washing dishes only when the dishwasher is full

Explanation:

8 0

2 years ago

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