And the cold air moves up wards where it heatens
Answer:
Explanation:
Please try to take a better photo as it is difficult to read.
For the first case, it is a small force to the right as there is a small velocity change.
For the second case, there is no force as there is no change in velocity
For the third case, it is a large (could be medium but photo is too blurry) force to the right as there is a large change in velocity.
Answer: F = 19.2 N
Explanation: Given that the initial Force = 3.6N
The formula involved is
F = GMm/r^2
Substitute the force F
3.6 = GMm/r^2
If one of the masses is tripled and the distance between the masses is quadrupled. We have
3.6 = (G × 3Mm)/(4r)^2
Where G will be constant.
3.6 = 3GMm/16r^2
Separate the fraction of number
3.6 = 3/16 × GMm/r^2
Make GMm/r^2 the subject of formula
(3.6 × 16)/3 = GMm/r^2
19.2 = GMm/r^2
Therefore, the new force of attraction is 19.2 N
Answer:
a= 289 m/s²
Explanation:
Given that
mass , m =1 kg
Radius of the path ,R= 1.09 m
The maximum speed ,V= 17 m/s
Lets take the maximum acceleration = a
The radial acceleration is given as
V=Velocity
R=Radius of the circular path
Now by putting the values in the above equation we get
a= 289 m/s²
