Somebody help me fast This is correct?!

Becky d james have a total of 4 2/8 feet of yarn. Becky has 1 5/8 feet of yarn. How many feet of yarn does james have?

ra1l [238]

Let
x----------------> feet of yarn of Becky
y----------------> feet of yarn of James

we know that
4 2/8------> 4 1/4--------> (4*4+1)/4-----> 17/4
1 5/8------> (1*8+5)/8-----> 13/5
x+y=4 2/8-------> x+y=17/4----> equation 1
x=1 5/8--------> x=13/5------> equation 2
substitute 2 in 1
[13/5]+y=17/4------> y=(17/4)-(13/5)----> y=[5*17-4*13]/20
y=(85-52)/20-----> y=33/20----> y=1.65-----> y=1 65/100----> y=1 13/20

the answer is
james have 1 13/20 ft of yarn

7 0

2 years ago

Your soccer team wants to buy t-shirts. you call two different companies about prices.company a has a 50$ fee to set up the logo

GrogVix [38]

Answer:

Company A

Step-by-step explanation:

A) 15 + 50 = 65

B) 95 + 12 = 107

$65\leq 107$

$Company A \leq Company B$

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4 0

2 years ago

Read 2 more answers

Do u have algebra answers

8090 [49]

What's the algebra question ?

8 0

2 years ago

Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that

Bond [772]

Taylor series is $f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2} }$

To find the Taylor series for f(x) = ln(x) centering at 9, we need to observe the pattern for the first four derivatives of f(x). From there, we can create a general equation for f(n). Starting with f(x), we have

f(x) = ln(x)

$f^{1}(x)= \frac{1}{x} \\f^{2}(x)= -\frac{1}{x^{2} }\\f^{3}(x)= -\frac{2}{x^{3} }\\f^{4}(x)= \frac{-6}{x^{4} }$

.

Since we need to have it centered at 9, we must take the value of f(9), and so on.

f(9) = ln(9)

$f^{1}(9)= \frac{1}{9} \\f^{2}(9)= -\frac{1}{9^{2} }\\f^{3}(x)= -\frac{1(2)}{9^{3} }\\f^{4}(x)= \frac{-1(2)(3)}{9^{4} }$

.

Following the pattern, we can see that for $f^{n}(x)$ ,

$f^{n}(x)=(-1)^{n-1}\frac{1.2.3.4.5...........(n-1)}{9^{n} } \\f^{n}(x)=(-1)^{n-1}\frac{(n-1)!}{9^{n}}$

This applies for n ≥ 1, Expressing f(x) in summation, we have

$\sum_{n=0}^{\infinite} \frac{f^{n}(9) }{n!} (x-9)^{2}$

Combining ln2 with the rest of series, we have

$f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2} }$

Taylor series is $f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2} }$

Find out more information about taylor series here

brainly.com/question/13057266

#SPJ4

3 0

1 year ago

1. -3 2/5 + b = 8 1/5 2. -7/3 n = -42 PLZ HELP ASAP I WILL MARK BRAINLIEST

diamong [38]

1. Convert the mixed numbers into improper numbers (-3 2/5 = -17/5 and 8 1/5 = 41/5). Then add 17/5 to both sides when means b=58/5

2. Multiply both sides by the reciprocal of -7/3 (which is -3/7). So n=18

7 0

2 years ago