Answer:
28.01g
Explanation:
Given the weight of one mole of Cabon as 12.01g and that of oxygen as 16.00g.
The molecular weight of a compound can be gotten by adding the molar weights of the elements that constitutes the compound .
The molecular weight of the compound CO is therefore
equal to the sum of the weight of both elements.
That’s = 12.01g + 16.00g
= 28.01g
Therefore, the molecular weight of CO is 28.01g
Answer:
Explanation:
We shall find out volume of air at NTP or at 273 K and 10⁵ Pa ( 1 atm )
Let it be V₂
V₂ = 7.87 litres
22.4 litres of any gas is equivalent to 1 mole
7.87 litres of air will be equivalent to
7.87 / 22.4 moles
= .35 moles .
Answer:
Sodium is most reactive metal among these. Sodium is present in group one. It is alkali metal.
Explanation:
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