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2 years ago

2(y-5)=(3y-2) can’t solve it

2 answers:

4 0

Hey :)

y = -8

Use the distributive property to multiply 2 by y−5
2y−10 = 3y−2

Subtract 3y from both sides
2y −10 −3y = −2

Combine 2y and −3y to get −y
−y −10 = −2

Add 10 to both sides
−y = −2 + 10

Add −2 and 10 to get 8
−y = 8

Multiply both sides by −1
y = −8

Hope this helps!

GaryK [48]2 years ago

3 0

Answer:

y=-8

Step-by-step explanation:

2(y-5)=(3y-2)

2y-10=3y-2

-8=y

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Find an equation for the perpendicular Bisector of the line segment whose endpoints are (-9,-8) and (7,-4

Alina [70]

equation for the perpendicular Bisector of the line segment whose endpoints are (-9,-8) and (7,-4)

Perpendicular bisector lies at the midpoint of a line

Lets find mid point of (-9,-8) and (7,-4)

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$\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2}$

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midpoint is (-1, -6)

Now find the slope of the given line

(-9,-8) and (7,-4)

$slope = \frac{y2-y1}{x2-x1} = \frac{-4-(-8)}{7-(-9)}$

$slope = \frac{-4+8}{7+9}= \frac{4}{16} =\frac{1}{4}$

Slope of perpendicular line is negative reciprocal of slope of given line

So slope of perpendicular line is -4

slope = -4 and midpoint is (-1,-6)

y - y1 = m(x-x1)

y - (-6) = -4(x-(-1))

y + 6 = -4(x+1)

y + 6 = -4x -4

Subtract 6 on both sides

y = -4x -4-6

y= -4x -10

equation for the perpendicular Bisector y = -4x - 10

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2 years ago

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ycow [4]

Answer:

Step-by-step explanation: 3root5x^2 + 25x - 10root5 = 0

3xroot5 + 25x - 10root5 = 0 [ root x^2 = x]

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28x root 5/root5 =10

28x=10

x = 10/28

x = 0.35

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